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integral of ln(x)/x

What is the integral of ln(x)/x?

The integral of \ln(x)/x is \frac{1}{2}\ln^2(x) + C.

Solution. We want to determine the integral of \ln(x)/x:
\begin{align*}
\int \frac{\ln(x)}{x} dx.
\end{align*}
We will use the substitution method. Let u = \ln(x), then we know from here that du = \frac{1}{x}dx. So we get the following:
\begin{align*}
\int \frac{\ln(x)}{x} dx &= \int u du \\
&= \frac{1}{2}u^2 + C \\
&= \frac{1}{2}\ln^2(x) + C.
\end{align*}
Therefore, the integral of \ln(x)/x is \frac{1}{2}\ln^2(x) + C.

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