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		<title>Prove that sin^2(x) + cos^2(x) = 1</title>
		<link>https://www.epsilonify.com/mathematics/calculus/prove-that-sin-square-x-plus-cos-square-x-is-1/</link>
					<comments>https://www.epsilonify.com/mathematics/calculus/prove-that-sin-square-x-plus-cos-square-x-is-1/#respond</comments>
		
		<dc:creator><![CDATA[The Mathematician]]></dc:creator>
		<pubDate>Tue, 27 Dec 2022 13:00:56 +0000</pubDate>
				<category><![CDATA[Calculus]]></category>
		<category><![CDATA[Mathematics]]></category>
		<category><![CDATA[sin^2(x) + cos^2(x) = 1]]></category>
		<guid isPermaLink="false">https://www.epsilonify.com/?p=1818</guid>

					<description><![CDATA[<p>Show that . Proof. Recall the next addition formula for Cosine: Now take . Then we get: So we get .</p>
<p>The post <a href="https://www.epsilonify.com/mathematics/calculus/prove-that-sin-square-x-plus-cos-square-x-is-1/">Prove that sin^2(x) + cos^2(x) = 1</a> appeared first on <a href="https://www.epsilonify.com">Epsilonify</a>.</p>
]]></description>
										<content:encoded><![CDATA[Show that <span class="katex-eq" data-katex-display="false">\sin^2(x) + \cos^2(x) = 1</span>.
<br>
<br>
<strong>Proof.</strong> Recall the next addition formula for Cosine:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
\cos(A-B) = \cos(A)\cos(B) + \sin(A)\sin(B).
\end{align*}</pre></div>

Now take <span class="katex-eq" data-katex-display="false">A = B = x</span>. Then we get:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
\cos(x - x) = \cos(x)\cos(x) + \sin(x)\sin(x) &\iff \cos(0) = \cos^2(x) + \sin^2(x) \\
&\iff 1 = \cos^2(x) + \sin^2(x).
\end{align*}</pre></div>

So we get <span class="katex-eq" data-katex-display="false">\sin^2(x) + \cos^2(x) = 1</span>.<p>The post <a href="https://www.epsilonify.com/mathematics/calculus/prove-that-sin-square-x-plus-cos-square-x-is-1/">Prove that sin^2(x) + cos^2(x) = 1</a> appeared first on <a href="https://www.epsilonify.com">Epsilonify</a>.</p>
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