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	<title>ln^3(x) Archives - Epsilonify</title>
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		<title>What is the Derivative of ln^3(x)?</title>
		<link>https://www.epsilonify.com/mathematics/calculus/what-is-the-derivative-of-ln-cubic-x/</link>
					<comments>https://www.epsilonify.com/mathematics/calculus/what-is-the-derivative-of-ln-cubic-x/#respond</comments>
		
		<dc:creator><![CDATA[The Mathematician]]></dc:creator>
		<pubDate>Mon, 14 Nov 2022 13:00:28 +0000</pubDate>
				<category><![CDATA[Calculus]]></category>
		<category><![CDATA[Mathematics]]></category>
		<category><![CDATA[Derivative of ln^3(x)]]></category>
		<category><![CDATA[ln^3(x)]]></category>
		<guid isPermaLink="false">https://www.epsilonify.com/?p=1534</guid>

					<description><![CDATA[<p>The derivative of is . Solution. Let , and such that . Using the chain rule, we can determine the derivative of : We saw here that , and . So we get: Together, we get: So, the derivative of is .</p>
<p>The post <a href="https://www.epsilonify.com/mathematics/calculus/what-is-the-derivative-of-ln-cubic-x/">What is the Derivative of ln^3(x)?</a> appeared first on <a href="https://www.epsilonify.com">Epsilonify</a>.</p>
]]></description>
										<content:encoded><![CDATA[The derivative of <span class="katex-eq" data-katex-display="false">\ln^3(x)</span> is <span class="katex-eq" data-katex-display="false">\frac{3\ln^2(x)}{x}</span>.
<br>
<br>
<strong>Solution.</strong> Let <span class="katex-eq" data-katex-display="false">F(x) = \ln^3(x)</span>, <span class="katex-eq" data-katex-display="false">f(u) = u^3</span> and <span class="katex-eq" data-katex-display="false">g(x) = \ln(x)</span> such that <span class="katex-eq" data-katex-display="false">F(x) = f(g(x))</span>. Using the chain rule, we can determine the derivative of <span class="katex-eq" data-katex-display="false">\ln^3(x)</span>:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
F'(x) = f'(g(x))g'(x).
\end{align*}</pre></div>

We saw <a href="https://www.epsilonify.com/mathematics/derivative-of-natural-logarithm-using-the-first-order-principle/">here</a> that <span class="katex-eq" data-katex-display="false">g'(x) = \frac{1}{x}</span>, and <span class="katex-eq" data-katex-display="false">f'(u) = 3u^2</span>. So we get:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
f'(g(x)) = 3g(x)^2 = 3\ln^2(x). 
\end{align*}</pre></div>

Together, we get:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
F'(x) &= f'(g(x))g'(x) \\
&= 3\ln^2(x) \frac{1}{x} \\
&= \frac{3\ln^2(x)}{x}.
\end{align*}</pre></div>

So, the derivative of <span class="katex-eq" data-katex-display="false">\ln^3(x)</span> is <span class="katex-eq" data-katex-display="false">\frac{3\ln^2(x)}{x}</span>.<p>The post <a href="https://www.epsilonify.com/mathematics/calculus/what-is-the-derivative-of-ln-cubic-x/">What is the Derivative of ln^3(x)?</a> appeared first on <a href="https://www.epsilonify.com">Epsilonify</a>.</p>
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