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		<title>What is the integral of sec^2(x)?</title>
		<link>https://www.epsilonify.com/mathematics/calculus/what-is-the-integral-of-sec-square-x/</link>
					<comments>https://www.epsilonify.com/mathematics/calculus/what-is-the-integral-of-sec-square-x/#respond</comments>
		
		<dc:creator><![CDATA[The Mathematician]]></dc:creator>
		<pubDate>Sat, 14 Jan 2023 13:00:10 +0000</pubDate>
				<category><![CDATA[Calculus]]></category>
		<category><![CDATA[Mathematics]]></category>
		<category><![CDATA[integral of sec^2(x)]]></category>
		<category><![CDATA[sec^2(x)]]></category>
		<guid isPermaLink="false">https://www.epsilonify.com/?p=1882</guid>

					<description><![CDATA[<p>The integral of is . Proof. In this case, it is easy to show what the integral is if you have seen derivatives. Notice that we have seen here that Taking the antiderivative of , we do directly see that: What about the integral of ? We do know that the derivative of is by [&#8230;]</p>
<p>The post <a href="https://www.epsilonify.com/mathematics/calculus/what-is-the-integral-of-sec-square-x/">What is the integral of sec^2(x)?</a> appeared first on <a href="https://www.epsilonify.com">Epsilonify</a>.</p>
]]></description>
										<content:encoded><![CDATA[The integral of <span class="katex-eq" data-katex-display="false">\sec^2(ax)</span> is <span class="katex-eq" data-katex-display="false">\frac{1}{a}\tan(ax) + C</span>.
<br>
<br>
<strong>Proof.</strong> In this case, it is easy to show what the integral <span class="katex-eq" data-katex-display="false">\sec^2(ax)</span> is if you have seen derivatives. Notice that we have seen <a href="https://www.epsilonify.com/mathematics/derivative-of-tan-x-using-first-principle-method/">here</a> that 

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
\frac{d}{dx} \tan(x) = \sec^2(x). 
\end{align*}</pre></div>

Taking the antiderivative of <span class="katex-eq" data-katex-display="false">\sec^2(x)</span>, we do directly see that:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
\int \sec^2(x)dx = \tan(x) + C'.
\end{align*}</pre></div>

What about the integral of <span class="katex-eq" data-katex-display="false">\sec^2(ax)</span>? We do know that the derivative of <span class="katex-eq" data-katex-display="false">\frac{1}{a}\tan(ax)</span> is <span class="katex-eq" data-katex-display="false">\sec^2(ax)</span> by using the chain rule. Therefore, taking antiderivative of <span class="katex-eq" data-katex-display="false">\sec^2(ax)</span>, we get:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
\int \sec^2(ax)dx = \frac{1}{a}\tan(ax) + C.
\end{align*}</pre></div>

So, the integral of <span class="katex-eq" data-katex-display="false">\sec^2(ax)</span> is <span class="katex-eq" data-katex-display="false">\frac{1}{a}\tan(ax) + C</span>.<p>The post <a href="https://www.epsilonify.com/mathematics/calculus/what-is-the-integral-of-sec-square-x/">What is the integral of sec^2(x)?</a> appeared first on <a href="https://www.epsilonify.com">Epsilonify</a>.</p>
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