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		<title>What is the integral of inverse e^x?</title>
		<link>https://www.epsilonify.com/mathematics/calculus/what-is-the-integral-of-inverse-exponential-to-the-power-x/</link>
					<comments>https://www.epsilonify.com/mathematics/calculus/what-is-the-integral-of-inverse-exponential-to-the-power-x/#respond</comments>
		
		<dc:creator><![CDATA[The Mathematician]]></dc:creator>
		<pubDate>Sun, 19 Mar 2023 13:00:27 +0000</pubDate>
				<category><![CDATA[Calculus]]></category>
		<category><![CDATA[Mathematics]]></category>
		<category><![CDATA[e^-x]]></category>
		<category><![CDATA[integral of e^-x]]></category>
		<guid isPermaLink="false">https://www.epsilonify.com/?p=2095</guid>

					<description><![CDATA[<p>The integral of is . Solution. We want to determine the integral of , i.e.: We will use the substitution method: let , then . Then we get the following integral: Therefore, the integral of is .</p>
<p>The post <a href="https://www.epsilonify.com/mathematics/calculus/what-is-the-integral-of-inverse-exponential-to-the-power-x/">What is the integral of inverse e^x?</a> appeared first on <a href="https://www.epsilonify.com">Epsilonify</a>.</p>
]]></description>
										<content:encoded><![CDATA[The integral of <span class="katex-eq" data-katex-display="false">e^{-x}</span> is <span class="katex-eq" data-katex-display="false">-e^{-x} + C</span>.
<br>
<br>
<strong>Solution.</strong> We want to determine the integral of <span class="katex-eq" data-katex-display="false">e^{-x}</span>, i.e.:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
\int \frac{1}{e^x} dx = \int e^{-x}dx.
\end{align*}</pre></div>

We will use the substitution method: let <span class="katex-eq" data-katex-display="false">u = -x</span>, then <span class="katex-eq" data-katex-display="false">du = -dx</span>. Then we get the following integral:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
\int e^{-x} dx &= - \int e^u du \\
&= -e^u + C \\
&= -e^{-x} + C. 
\end{align*}</pre></div>

Therefore, the integral of <span class="katex-eq" data-katex-display="false">e^{-x}</span> is <span class="katex-eq" data-katex-display="false">-e^{-x} + C</span>.<p>The post <a href="https://www.epsilonify.com/mathematics/calculus/what-is-the-integral-of-inverse-exponential-to-the-power-x/">What is the integral of inverse e^x?</a> appeared first on <a href="https://www.epsilonify.com">Epsilonify</a>.</p>
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