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	<title>derivative of sin(ln(x)) Archives - Epsilonify</title>
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		<title>What is the derivative of sin(ln(x))?</title>
		<link>https://www.epsilonify.com/mathematics/calculus/what-is-the-derivative-of-sinlnx/</link>
					<comments>https://www.epsilonify.com/mathematics/calculus/what-is-the-derivative-of-sinlnx/#respond</comments>
		
		<dc:creator><![CDATA[The Mathematician]]></dc:creator>
		<pubDate>Thu, 23 Mar 2023 13:00:23 +0000</pubDate>
				<category><![CDATA[Calculus]]></category>
		<category><![CDATA[Mathematics]]></category>
		<category><![CDATA[derivative of sin(ln(x))]]></category>
		<category><![CDATA[sin(ln(x))]]></category>
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					<description><![CDATA[<p>The derivative of is . Solution. To determine the derivative , we will use the chain rule: where and . We have seen here and here that . So we get: Combining everything, we get: Therefore, the derivative of is .</p>
<p>The post <a href="https://www.epsilonify.com/mathematics/calculus/what-is-the-derivative-of-sinlnx/">What is the derivative of sin(ln(x))?</a> appeared first on <a href="https://www.epsilonify.com">Epsilonify</a>.</p>
]]></description>
										<content:encoded><![CDATA[The derivative of <span class="katex-eq" data-katex-display="false">\sin(\ln(x))</span> is <span class="katex-eq" data-katex-display="false">\cos(\ln(x))/x</span>.
<br>
<br>
<strong>Solution.</strong> To determine the derivative <span class="katex-eq" data-katex-display="false">F(x) = f(g(x)) = \sin(\ln(x))</span>, we will use the chain rule:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
F'(x) = f'(g(x))g'(x),
\end{align*}</pre></div>

where <span class="katex-eq" data-katex-display="false">f(u) = \sin(u)</span> and <span class="katex-eq" data-katex-display="false">g(x) = \ln(x)</span>. We have seen <a href="https://www.epsilonify.com/mathematics/derivative-of-sin-x-using-first-principle-method/">here</a> <span class="katex-eq" data-katex-display="false">f'(u) = \cos(u)</span> and <a href="https://www.epsilonify.com/mathematics/derivative-of-natural-logarithm-using-the-first-principle-of-derivatives/">here</a> that <span class="katex-eq" data-katex-display="false">g'(x) = \frac{1}{x}</span>. So we get:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
f'(g(x)) = \cos(g(x)) = \cos(\ln(x)).
\end{align*}</pre></div>

Combining everything, we get:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
F'(x) &= f'(g(x))g'(x) \\
&= \cos(\ln(x))\frac{1}{x} \\
&= \frac{\cos(\ln(x))}{x}.
\end{align*}</pre></div>

Therefore, the derivative of <span class="katex-eq" data-katex-display="false">\sin(\ln(x))</span> is <span class="katex-eq" data-katex-display="false">\cos(\ln(x))/x</span>.<p>The post <a href="https://www.epsilonify.com/mathematics/calculus/what-is-the-derivative-of-sinlnx/">What is the derivative of sin(ln(x))?</a> appeared first on <a href="https://www.epsilonify.com">Epsilonify</a>.</p>
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