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	<title>cot^3(x) Archives - Epsilonify</title>
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		<title>What is the derivative of cot^3(x)?</title>
		<link>https://www.epsilonify.com/mathematics/calculus/what-is-the-derivative-of-cot-cubed-x/</link>
					<comments>https://www.epsilonify.com/mathematics/calculus/what-is-the-derivative-of-cot-cubed-x/#respond</comments>
		
		<dc:creator><![CDATA[The Mathematician]]></dc:creator>
		<pubDate>Fri, 28 Apr 2023 13:00:22 +0000</pubDate>
				<category><![CDATA[Calculus]]></category>
		<category><![CDATA[Mathematics]]></category>
		<category><![CDATA[cot^3(x)]]></category>
		<category><![CDATA[derivative of cot^3(x)]]></category>
		<guid isPermaLink="false">https://www.epsilonify.com/?p=2249</guid>

					<description><![CDATA[<p>The derivative of is . Solution. Let , where and . To determine the derivative of , we need to use the chain rule: It is easy to see that and we saw here that . So we get: Therefore, we get the following derivative: Therefore, the derivative of is .</p>
<p>The post <a href="https://www.epsilonify.com/mathematics/calculus/what-is-the-derivative-of-cot-cubed-x/">What is the derivative of cot^3(x)?</a> appeared first on <a href="https://www.epsilonify.com">Epsilonify</a>.</p>
]]></description>
										<content:encoded><![CDATA[The derivative of <span class="katex-eq" data-katex-display="false">\cot^3(x)</span> is <span class="katex-eq" data-katex-display="false">-3 \cot^2(x) \csc^2(x)</span>.
<br>
<br>
<strong>Solution.</strong> Let <span class="katex-eq" data-katex-display="false">F(x) = f(g(x)) = \cot^3(x)</span>, where <span class="katex-eq" data-katex-display="false">f(u) = u^3</span> and <span class="katex-eq" data-katex-display="false">g(x) = \cot(x)</span>. To determine the derivative of <span class="katex-eq" data-katex-display="false">\cot^3(x)</span>, we need to use the chain rule:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
F'(x) = f'(g(x))g'(x).
\end{align*}</pre></div>

It is easy to see that <span class="katex-eq" data-katex-display="false">f'(u) = \frac{d}{du} u^3 = 3u^2</span> and we saw <a href="https://www.epsilonify.com/mathematics/what-is-the-derivative-of-cotx/">here</a> that <span class="katex-eq" data-katex-display="false">g'(x) = -\csc^2(x)</span>. So we get:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
f'(g(x)) = 3g(x)^2 = 3\cot^2(x) \quad \text{and} \quad g'(x) = -\csc^2(x).
\end{align*}</pre></div>

Therefore, we get the following derivative:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
F'(x) &= f'(g(x))g'(x) \\
&= 3\cot^2(x)\cdot (-\csc^2(x)) \\
&= -3 \cot^2(x) \csc^2(x).
\end{align*}</pre></div>

Therefore, the derivative of <span class="katex-eq" data-katex-display="false">\cot^3(x)</span> is <span class="katex-eq" data-katex-display="false">-3 \cot^2(x) \csc^2(x)</span>.<p>The post <a href="https://www.epsilonify.com/mathematics/calculus/what-is-the-derivative-of-cot-cubed-x/">What is the derivative of cot^3(x)?</a> appeared first on <a href="https://www.epsilonify.com">Epsilonify</a>.</p>
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		<title>What is the integral of cot^3(x)?</title>
		<link>https://www.epsilonify.com/mathematics/calculus/what-is-the-integral-of-cot-cubed-x/</link>
					<comments>https://www.epsilonify.com/mathematics/calculus/what-is-the-integral-of-cot-cubed-x/#respond</comments>
		
		<dc:creator><![CDATA[The Mathematician]]></dc:creator>
		<pubDate>Thu, 23 Feb 2023 13:00:18 +0000</pubDate>
				<category><![CDATA[Calculus]]></category>
		<category><![CDATA[Mathematics]]></category>
		<category><![CDATA[cot^3(x)]]></category>
		<category><![CDATA[integral of cot^3(x)]]></category>
		<guid isPermaLink="false">https://www.epsilonify.com/?p=2009</guid>

					<description><![CDATA[<p>The integral of is . Solution. We want to determine the integral of , which can be simplified by using , which we have proven earlier: We know seen here integral of is plus some constant. So we have: We will apply the substitution method. Let , then which we have seen here. Then we [&#8230;]</p>
<p>The post <a href="https://www.epsilonify.com/mathematics/calculus/what-is-the-integral-of-cot-cubed-x/">What is the integral of cot^3(x)?</a> appeared first on <a href="https://www.epsilonify.com">Epsilonify</a>.</p>
]]></description>
										<content:encoded><![CDATA[The integral of <span class="katex-eq" data-katex-display="false">\cot^3(x)</span> is <span class="katex-eq" data-katex-display="false">-\frac{1}{2}\csc^2(x) - \ln \lvert \sin(x) \rvert + C</span>.
<br>
<br>
<strong>Solution.</strong> We want to determine the integral of <span class="katex-eq" data-katex-display="false">\cot^3(x)</span>, which can be simplified by using <span class="katex-eq" data-katex-display="false">\cot^2 =  \csc^2(x) - 1</span>, which we have <a href="https://www.epsilonify.com/mathematics/prove-that-1-plus-cot-square-x-is-csc-square-x/">proven</a> earlier:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
\int \cot^3(x) dx = \int (\csc^2(x) - 1)\cot(x) dx = \int \csc^2(x)\cot(x) dx - \int \cot(x)dx. 
\end{align*}</pre></div>

We know seen <a href="https://www.epsilonify.com/mathematics/what-is-the-integral-of-cotx/">here</a> integral of <span class="katex-eq" data-katex-display="false">\cot(x)</span> is <span class="katex-eq" data-katex-display="false">\ln \lvert \sin(x) \rvert</span> plus some constant. So we have:


 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
\int \csc^2(x)\cot(x) dx - \int \cot(x)dx = \int \csc^2(x)\cot(x) dx - \ln \lvert \sin(x) \rvert.
\end{align*}</pre></div>

We will apply the substitution method. Let <span class="katex-eq" data-katex-display="false">u = \csc(x)</span>, then <span class="katex-eq" data-katex-display="false">du = -\csc(x)\cot(x)dx</span> which we have seen <a href="https://www.epsilonify.com/mathematics/derivative-of-cot-x-using-first-principle-of-derivatives/">here</a>. Then we get the final result everything combined:

 <div class="wp-block-katex-display-block katex-eq" data-katex-display="true"><pre>\begin{align*}
\int \cot^3(x) dx &=  \int (\csc^2(x) - 1)\cot(x) dx \\
&= \int \csc^2(x)\cot(x) dx - \int \cot(x)dx \\
&= \int \csc^2(x)\cot(x) dx - \ln \lvert \sin(x) \rvert \\
&= - \int u du - \ln \lvert \sin(x) \rvert \\
&= -\frac{1}{2} u^2 - \ln \lvert \sin(x) \rvert + C \\
&= -\frac{1}{2} \csc^2(x) - \ln \lvert \sin(x) \rvert + C.
\end{align*}</pre></div>

Therefore, the integral of <span class="katex-eq" data-katex-display="false">\cot^3(x)</span> is <span class="katex-eq" data-katex-display="false">-\frac{1}{2}\csc^2(x) - \ln \lvert \sin(x) \rvert + C</span>.<p>The post <a href="https://www.epsilonify.com/mathematics/calculus/what-is-the-integral-of-cot-cubed-x/">What is the integral of cot^3(x)?</a> appeared first on <a href="https://www.epsilonify.com">Epsilonify</a>.</p>
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